Grade: Grade 7 Subject: Mathematics Unit: Probability Lesson: 4 of 6 SAT: ProblemSolving+DataAnalysis ACT: Math

Compound Events

Find probabilities when two or more events occur together.

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Types of Compound Events

  • Independent events: One event does not affect the other (flip coin, roll die)
  • Dependent events: One event affects the probability of the other (drawing cards without replacement)
  • "And" probability: P(A and B) = P(A) x P(B) for independent events
  • "Or" probability: P(A or B) = P(A) + P(B) - P(A and B)

Practice

Question 1: You flip a coin and roll a die. What is P(heads and 6)?

Answer

P(heads) = 1/2, P(6) = 1/6. P(heads and 6) = 1/2 x 1/6 = 1/12.

Question 2: You flip two coins. What is P(both heads)?

Answer

P(heads) x P(heads) = 1/2 x 1/2 = 1/4.

Question 3: A bag has 3 red and 2 blue marbles. You draw one, replace it, draw again. P(both red)?

Answer

P(red) = 3/5 each time. P(both red) = 3/5 x 3/5 = 9/25.

Question 4: Roll two dice. What is P(both even)?

Answer

P(even) = 3/6 = 1/2. P(both even) = 1/2 x 1/2 = 1/4.

Question 5: A spinner has sections 1-4. Spin twice. P(same number both times)?

Answer

P(1,1) + P(2,2) + P(3,3) + P(4,4) = 4 x (1/4 x 1/4) = 4 x 1/16 = 1/4.

Question 6: Bag has 4 red, 6 blue. Draw one without replacement, then another. P(both blue)?

Answer

P(first blue) = 6/10. P(second blue) = 5/9. P(both) = 6/10 x 5/9 = 30/90 = 1/3.

Question 7: Roll a die. What is P(even or greater than 4)?

Answer

Even: {2,4,6}. Greater than 4: {5,6}. P(even or >4) = P(even) + P(>4) - P(both) = 3/6 + 2/6 - 1/6 = 4/6 = 2/3.

Question 8: Flip three coins. What is P(at least one head)?

Answer

P(at least one head) = 1 - P(no heads) = 1 - (1/2)^3 = 1 - 1/8 = 7/8.

Question 9: Draw a card from a standard deck. P(red or face card)?

Answer

Red: 26/52. Face: 12/52. Red face: 6/52. P = 26/52 + 12/52 - 6/52 = 32/52 = 8/13.

Question 10: Roll two dice. What is P(sum = 7)?

Answer

Outcomes with sum 7: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6 ways. Total: 36. P = 6/36 = 1/6.