Grade: Grade 12 Subject: Mathematics Unit: Quantitative Reasoning SAT: ProblemSolving+DataAnalysis ACT: Math

Financial Mathematics

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Financial mathematics provides the tools to make informed decisions about money, investments, loans, and savings. Understanding these concepts is essential for personal financial planning and is frequently tested on standardized exams.

Simple Interest

Simple Interest Formula

I = P × r × t

Where:

  • I = Interest earned or paid
  • P = Principal (initial amount)
  • r = Annual interest rate (as a decimal)
  • t = Time in years

The total amount after simple interest is: A = P + I = P(1 + rt)

Simple interest is calculated only on the original principal. It's commonly used for short-term loans and some bonds.

Compound Interest

Compound Interest Formula

A = P(1 + r/n)^(nt)

Where:

  • A = Final amount (principal + interest)
  • P = Principal (initial investment)
  • r = Annual interest rate (as a decimal)
  • n = Number of times interest compounds per year
  • t = Time in years
Compounding Frequency n value Description
Annually 1 Once per year
Semi-annually 2 Twice per year
Quarterly 4 Four times per year
Monthly 12 Twelve times per year
Daily 365 Every day

Continuous Compounding

Continuous Compound Interest

A = Pe^(rt)

When interest compounds continuously (infinitely often), we use the natural exponential function where e ≈ 2.71828.

Present Value and Future Value

Present Value (PV)

PV = FV / (1 + r/n)^(nt)

Present value answers: "How much must I invest today to have a specific amount in the future?"

Future Value (FV)

FV = PV(1 + r/n)^(nt)

Future value answers: "What will my investment be worth at a future date?"

Annuities

An annuity is a series of equal payments made at regular intervals.

Future Value of an Ordinary Annuity

FV = PMT × [(1 + r/n)^(nt) - 1] / (r/n)

This calculates the total value when making regular deposits (payments made at the end of each period).

Present Value of an Ordinary Annuity

PV = PMT × [1 - (1 + r/n)^(-nt)] / (r/n)

This calculates how much a series of future payments is worth today.

Loan Amortization

Monthly Payment Formula

PMT = P × [r(1 + r)^n] / [(1 + r)^n - 1]

Where:

  • PMT = Monthly payment
  • P = Principal (loan amount)
  • r = Monthly interest rate (annual rate / 12)
  • n = Total number of payments

Understanding Amortization

In an amortized loan:

  • Each payment is the same amount
  • Early payments are mostly interest
  • Later payments are mostly principal
  • Total interest paid = (PMT × n) - P

Annual Percentage Rate (APR) vs. Annual Percentage Yield (APY)

Term Definition Use
APR Annual Percentage Rate - stated annual rate without compounding Loans, credit cards
APY Annual Percentage Yield - effective rate including compounding Savings accounts, investments

APY Formula

APY = (1 + r/n)^n - 1

APY shows the true annual return when interest compounds multiple times per year.

SAT/ACT Connection

Financial math problems on standardized tests typically involve:

  • Calculating simple and compound interest
  • Comparing investment options
  • Understanding exponential growth in financial contexts
  • Interpreting loan terms and payments
  • Percent increase/decrease problems

Examples

Example 1: Simple Interest

Problem: You invest $5,000 in a bond that pays 4.5% simple annual interest. How much interest will you earn after 3 years? What will be the total value?

Solution:

Using I = P × r × t:

I = $5,000 × 0.045 × 3

I = $675

Total value: A = P + I = $5,000 + $675 = $5,675

You will earn $675 in interest, giving a total of $5,675.

Example 2: Compound Interest Comparison

Problem: You have $10,000 to invest for 5 years at 6% annual interest. Compare the final amounts with: (a) annual compounding, (b) monthly compounding, and (c) continuous compounding.

Solution:

(a) Annual compounding (n = 1):

A = 10,000(1 + 0.06/1)^(1×5) = 10,000(1.06)^5

A = 10,000 × 1.3382 = $13,382.26

(b) Monthly compounding (n = 12):

A = 10,000(1 + 0.06/12)^(12×5) = 10,000(1.005)^60

A = 10,000 × 1.3489 = $13,488.50

(c) Continuous compounding:

A = 10,000 × e^(0.06×5) = 10,000 × e^0.3

A = 10,000 × 1.3499 = $13,498.59

More frequent compounding yields higher returns: continuous > monthly > annual.

Example 3: Present Value

Problem: You want to have $50,000 in 10 years for a down payment on a house. If your investment earns 5% compounded monthly, how much must you invest today?

Solution:

Using PV = FV / (1 + r/n)^(nt):

PV = 50,000 / (1 + 0.05/12)^(12×10)

PV = 50,000 / (1.004167)^120

PV = 50,000 / 1.6470

PV = $30,353.35

You need to invest approximately $30,353.35 today.

Example 4: Future Value of an Annuity

Problem: You contribute $500 per month to a retirement account that earns 7% annually, compounded monthly. How much will you have after 30 years?

Solution:

Using FV = PMT × [(1 + r/n)^(nt) - 1] / (r/n):

Monthly rate: r/n = 0.07/12 = 0.005833

Number of payments: nt = 12 × 30 = 360

FV = 500 × [(1.005833)^360 - 1] / 0.005833

FV = 500 × [8.1165 - 1] / 0.005833

FV = 500 × 7.1165 / 0.005833

FV = 500 × 1,220.42

FV = $610,210

Your retirement account will be worth approximately $610,210.

Note: Total contributions = $500 × 360 = $180,000, so interest earned = $430,210!

Example 5: Loan Payment Calculation

Problem: You take out a $250,000 mortgage at 6.5% annual interest for 30 years. (a) What is your monthly payment? (b) How much total interest will you pay over the life of the loan?

Solution:

(a) Monthly payment:

Monthly rate: r = 0.065/12 = 0.005417

Number of payments: n = 30 × 12 = 360

PMT = 250,000 × [0.005417(1.005417)^360] / [(1.005417)^360 - 1]

PMT = 250,000 × [0.005417 × 6.9916] / [6.9916 - 1]

PMT = 250,000 × 0.03787 / 5.9916

PMT = 250,000 × 0.006321

PMT = $1,580.17 per month

(b) Total interest:

Total paid = $1,580.17 × 360 = $568,861.20

Total interest = $568,861.20 - $250,000 = $318,861.20

You will pay more than the original loan amount in interest alone!

Practice

1. You deposit $2,000 in an account earning 3% simple annual interest. How much will be in the account after 4 years?

A) $2,060   B) $2,240   C) $2,251.02   D) $2,400

2. An investment of $8,000 earns 5% interest compounded quarterly. What is the value after 3 years?

A) $9,200.00   B) $9,261.00   C) $9,287.47   D) $9,310.55

3. Which option yields the highest return on a $5,000 investment over 2 years?

A) 6% simple interest   B) 5.8% compounded annually   C) 5.7% compounded monthly   D) 5.6% compounded daily

4. You want to have $20,000 in 6 years. If your account earns 4% compounded monthly, how much should you deposit today?

A) $15,724.31   B) $15,789.45   C) $16,000.00   D) $17,391.30

5. Calculate the APY for an account with 4.8% APR compounded monthly.

A) 4.80%   B) 4.87%   C) 4.91%   D) 5.00%

6. Maria invests $300 per month for 20 years in an account earning 6% annually, compounded monthly. What is the future value?

A) $72,000   B) $110,357   C) $138,612   D) $147,084

7. A car loan of $28,000 at 4.5% annual interest is to be paid off in 5 years. What is the monthly payment?

A) $466.67   B) $521.84   C) $538.33   D) $583.33

8. How long will it take for an investment to double if it earns 8% compounded annually? (Use the Rule of 72 approximation)

A) 7 years   B) 9 years   C) 10 years   D) 12 years

9. A $15,000 investment grows to $21,000 in 5 years with annual compounding. What was the interest rate?

A) 6.0%   B) 6.5%   C) 6.96%   D) 8.0%

10. You take out a $180,000 mortgage at 5.25% for 15 years. What is the total interest paid over the life of the loan if the monthly payment is $1,449.42?

A) $47,250   B) $80,895.60   C) $141,750   D) $260,895.60

Click to reveal answers
  1. B) $2,240 - Using A = P(1 + rt) = 2,000(1 + 0.03 × 4) = 2,000(1.12) = $2,240
  2. C) $9,287.47 - A = 8,000(1 + 0.05/4)^(4×3) = 8,000(1.0125)^12 = $9,287.47
  3. A) 6% simple interest - A: $5,600; B: $5,596.82; C: $5,598.08; D: $5,591.43. Simple interest at 6% yields the most.
  4. A) $15,724.31 - PV = 20,000/(1 + 0.04/12)^(12×6) = 20,000/1.2718 = $15,724.31
  5. C) 4.91% - APY = (1 + 0.048/12)^12 - 1 = (1.004)^12 - 1 = 0.0491 = 4.91%
  6. C) $138,612 - FV = 300 × [(1.005)^240 - 1]/0.005 = 300 × 462.04 = $138,612
  7. B) $521.84 - Using PMT formula with r = 0.045/12 and n = 60, PMT = $521.84
  8. B) 9 years - Rule of 72: 72/8 = 9 years (actual is about 9.01 years)
  9. C) 6.96% - 21,000 = 15,000(1 + r)^5, so (1 + r)^5 = 1.4, r = 1.4^(1/5) - 1 = 0.0696 = 6.96%
  10. B) $80,895.60 - Total paid = $1,449.42 × 180 = $260,895.60; Interest = $260,895.60 - $180,000 = $80,895.60

Check Your Understanding

1. Why does compound interest grow faster than simple interest, and what real-world implications does this have for long-term savings?

Show answer

Compound interest grows faster because interest is earned not only on the original principal but also on previously accumulated interest - this creates exponential rather than linear growth. The practical implication is enormous for long-term savings: starting to save early, even with small amounts, can result in dramatically larger balances than starting later with larger amounts. For example, someone who invests $200/month starting at age 25 will likely have more at retirement than someone who invests $400/month starting at age 35, despite contributing less total money. This is why financial advisors emphasize "time in the market" and early saving habits.

2. Explain the relationship between APR and APY. When would knowing the difference be important for a consumer?

Show answer

APR (Annual Percentage Rate) is the stated interest rate without accounting for compounding, while APY (Annual Percentage Yield) shows the effective annual rate including compounding effects. The difference matters in several situations: (1) When comparing savings accounts, a higher APY means more earnings - two accounts with the same APR but different compounding frequencies will have different APYs. (2) When borrowing, lenders often advertise APR while APY shows the true cost - a credit card with 18% APR compounded daily has an APY of about 19.7%. (3) For informed decision-making, consumers should compare APYs for savings and understand that advertised APRs on loans understate the actual interest cost when compounding occurs more than annually.

3. Why do you pay more interest in the early years of a mortgage than in the later years, even though the payment stays the same?

Show answer

In an amortized loan, each payment covers both interest and principal, but the proportion changes over time. Interest is calculated on the remaining balance, so when the balance is high (early years), the interest portion is large. As you pay down the principal, less interest accrues each month, so more of your fixed payment goes toward principal. For example, on a $200,000 mortgage at 6%, your first payment might be $1,199, with $1,000 going to interest and only $199 to principal. Years later, the same $1,199 payment might have only $200 going to interest and $999 to principal. This is why making extra principal payments early in a loan can save substantial interest over time - it reduces the balance that interest is calculated on for all remaining payments.

4. How does the concept of present value help in making financial decisions? Give an example of a situation where calculating present value would be useful.

Show answer

Present value allows us to compare money received or paid at different times by expressing all values in today's dollars, accounting for the time value of money (the fact that money available now is worth more than the same amount later due to earning potential). Examples of useful applications: (1) Lottery winnings - choosing between a $1 million lump sum today or $50,000 per year for 25 years requires calculating the present value of the annuity to make a fair comparison. (2) Business investments - evaluating whether to spend $100,000 now on equipment that will generate $30,000 per year in savings for 5 years. (3) Retirement planning - determining how much a pension promising $40,000/year is worth compared to a lump sum offer. (4) Legal settlements - calculating fair compensation for future lost wages in today's dollars. Present value is essential for any decision involving money flows at different times.

🚀 Next Steps

  • Review any concepts that felt challenging
  • Move on to the next lesson when ready
  • Return to practice problems periodically for review