The Mole Concept
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The Mole
A mole (symbol: mol) is the SI unit for measuring the amount of a substance. One mole contains exactly 6.022 x 10^23 particles (atoms, molecules, ions, or formula units). This number is called Avogadro's number.
Why Do We Need the Mole?
Atoms and molecules are incredibly tiny - far too small to count individually. The mole provides a practical way to work with enormous numbers of particles:
- Just as a "dozen" means 12 items, a "mole" means 6.022 x 10^23 items
- The mole connects the microscopic world (atoms) to the macroscopic world (grams)
- Chemical equations are balanced in terms of moles, allowing us to predict amounts of reactants and products
Avogadro's Number
Avogadro's number (NA) = 6.022 x 10^23 particles/mol. This is the number of particles in exactly one mole of any substance.
Visualizing Avogadro's Number
How big is 6.022 x 10^23? Consider these comparisons:
- If you counted one atom per second, it would take about 19 quadrillion years to count one mole of atoms
- One mole of pennies stacked would create a tower reaching from Earth to the sun and back over 400 million times
- One mole of sand grains would cover the entire United States to a depth of several feet
Molar Mass
Molar Mass
Molar mass is the mass of one mole of a substance, expressed in grams per mole (g/mol). Numerically, the molar mass in grams equals the atomic mass in atomic mass units (amu).
| Substance | Atomic/Formula Mass (amu) | Molar Mass (g/mol) |
|---|---|---|
| Carbon (C) | 12.01 amu | 12.01 g/mol |
| Oxygen (O) | 16.00 amu | 16.00 g/mol |
| Water (H2O) | 18.02 amu | 18.02 g/mol |
| Sodium Chloride (NaCl) | 58.44 amu | 58.44 g/mol |
| Glucose (C6H12O6) | 180.16 amu | 180.16 g/mol |
Calculating Molar Mass
To find the molar mass of a compound:
- Identify all elements in the formula
- Multiply each element's atomic mass by its subscript
- Add all the values together
Example: Molar Mass of H2SO4
- H: 2 atoms x 1.01 g/mol = 2.02 g/mol
- S: 1 atom x 32.07 g/mol = 32.07 g/mol
- O: 4 atoms x 16.00 g/mol = 64.00 g/mol
- Total: 98.09 g/mol
The Mole Triangle
Three quantities are related through the mole concept:
| Conversion | Formula | Relationship |
|---|---|---|
| Mass to Moles | moles = mass (g) / molar mass (g/mol) | Divide by molar mass |
| Moles to Mass | mass (g) = moles x molar mass (g/mol) | Multiply by molar mass |
| Moles to Particles | particles = moles x 6.022 x 10^23 | Multiply by Avogadro's number |
| Particles to Moles | moles = particles / 6.022 x 10^23 | Divide by Avogadro's number |
Molar Volume of Gases
Molar Volume at STP
At Standard Temperature and Pressure (STP) - defined as 0C (273 K) and 1 atm - one mole of any ideal gas occupies exactly 22.4 liters. This is called the molar volume.
| Gas | Moles | Volume at STP |
|---|---|---|
| Oxygen (O2) | 1 mol | 22.4 L |
| Nitrogen (N2) | 1 mol | 22.4 L |
| Hydrogen (H2) | 1 mol | 22.4 L |
| Any ideal gas | 1 mol | 22.4 L |
SAT/ACT Connection
Science sections may present data about chemical quantities and ask you to convert between grams, moles, and number of particles. Know your key conversion factors: molar mass connects grams to moles, and Avogadro's number connects moles to particles.
💡 Examples
Example 1: Calculating Molar Mass
Problem: Calculate the molar mass of calcium hydroxide, Ca(OH)2.
Solution:
Step 1: Identify atoms and their quantities:
- Ca: 1 atom
- O: 2 atoms (from the subscript outside parentheses)
- H: 2 atoms (from the subscript outside parentheses)
Step 2: Look up atomic masses and multiply:
- Ca: 1 x 40.08 g/mol = 40.08 g/mol
- O: 2 x 16.00 g/mol = 32.00 g/mol
- H: 2 x 1.01 g/mol = 2.02 g/mol
Step 3: Add all values:
Answer: 40.08 + 32.00 + 2.02 = 74.10 g/mol
Example 2: Converting Grams to Moles
Problem: How many moles are in 50.0 g of water (H2O)?
Solution:
Step 1: Find the molar mass of H2O:
- H: 2 x 1.01 = 2.02 g/mol
- O: 1 x 16.00 = 16.00 g/mol
- Total: 18.02 g/mol
Step 2: Use the formula: moles = mass / molar mass
Step 3: Calculate: 50.0 g / 18.02 g/mol = 2.77 mol
Answer: 2.77 moles of water
Example 3: Converting Moles to Number of Particles
Problem: How many molecules are in 0.50 moles of carbon dioxide (CO2)?
Solution:
Step 1: Use Avogadro's number: 1 mole = 6.022 x 10^23 particles
Step 2: Multiply moles by Avogadro's number:
0.50 mol x 6.022 x 10^23 molecules/mol
Step 3: Calculate: 3.01 x 10^23 molecules
Answer: 3.01 x 10^23 molecules of CO2
Example 4: Converting Particles to Grams
Problem: What is the mass of 1.50 x 10^24 atoms of iron (Fe)?
Solution:
Step 1: Convert atoms to moles:
moles = 1.50 x 10^24 atoms / 6.022 x 10^23 atoms/mol = 2.49 mol
Step 2: Find molar mass of Fe: 55.85 g/mol
Step 3: Convert moles to grams:
mass = 2.49 mol x 55.85 g/mol = 139 g
Answer: 139 grams of iron
Example 5: Using Molar Volume at STP
Problem: What volume does 3.5 moles of oxygen gas (O2) occupy at STP?
Solution:
Step 1: At STP, 1 mole of any gas = 22.4 L
Step 2: Multiply moles by molar volume:
Volume = 3.5 mol x 22.4 L/mol
Step 3: Calculate: 78.4 L
Answer: 78.4 liters at STP
✏️ Practice
1. Avogadro's number is approximately:
A) 6.022 x 10^20
B) 6.022 x 10^21
C) 6.022 x 10^22
D) 6.022 x 10^23
2. What is the molar mass of sulfuric acid (H2SO4)?
A) 49.1 g/mol
B) 98.1 g/mol
C) 80.1 g/mol
D) 34.1 g/mol
3. How many moles are in 44 g of CO2 (molar mass = 44 g/mol)?
A) 0.5 mol
B) 1.0 mol
C) 2.0 mol
D) 44 mol
4. One mole of any gas at STP occupies:
A) 1.0 L
B) 11.2 L
C) 22.4 L
D) 44.8 L
5. How many molecules are in 2.0 moles of water?
A) 3.01 x 10^23
B) 6.02 x 10^23
C) 1.20 x 10^24
D) 1.80 x 10^24
6. What is the mass of 0.25 moles of NaCl (molar mass = 58.44 g/mol)?
A) 14.6 g
B) 29.2 g
C) 58.4 g
D) 233.8 g
7. How many atoms are in one molecule of glucose (C6H12O6)?
A) 6
B) 12
C) 18
D) 24
8. The molar mass of an element is numerically equal to its:
A) Number of protons
B) Atomic number
C) Atomic mass in amu
D) Number of electrons
9. How many moles of oxygen atoms (not O2 molecules) are in 1 mole of H2O?
A) 0.5 mol
B) 1.0 mol
C) 2.0 mol
D) 3.0 mol
10. If 3.01 x 10^23 atoms of an element have a mass of 12 g, what is the molar mass of the element?
A) 6 g/mol
B) 12 g/mol
C) 24 g/mol
D) 36 g/mol
Click to reveal answers
- D - Avogadro's number is 6.022 x 10^23 particles per mole.
- B - H2SO4: 2(1.01) + 32.07 + 4(16.00) = 2.02 + 32.07 + 64.00 = 98.09 g/mol
- B - moles = 44 g / 44 g/mol = 1.0 mol
- C - At STP, one mole of any ideal gas occupies 22.4 L (molar volume).
- C - 2.0 mol x 6.022 x 10^23 = 1.20 x 10^24 molecules
- A - mass = 0.25 mol x 58.44 g/mol = 14.61 g
- D - C6H12O6 has 6 C + 12 H + 6 O = 24 atoms per molecule
- C - The molar mass in g/mol equals the atomic mass in amu.
- B - Each H2O molecule has 1 oxygen atom, so 1 mol H2O contains 1 mol O atoms.
- C - 3.01 x 10^23 is 0.5 mol. If 0.5 mol = 12 g, then 1 mol = 24 g/mol.
✅ Check Your Understanding
Question 1: Explain why the mole is sometimes called the "chemist's dozen." How does it serve a similar purpose?
Reveal Answer
Just as a "dozen" represents 12 items (making it easier to buy eggs or donuts without counting each one), a "mole" represents 6.022 x 10^23 particles. The mole allows chemists to work with countable, measurable amounts of substances rather than dealing with individual atoms or molecules. A dozen connects us to a convenient number of everyday objects; a mole connects us to a convenient amount of atoms/molecules that we can actually weigh on a balance. It's the bridge between the atomic scale (too small to measure directly) and the macroscopic scale (grams we can measure).
Question 2: Why is the molar mass of carbon-12 exactly 12 g/mol, while other elements have molar masses that aren't whole numbers?
Reveal Answer
The atomic mass unit (amu) was defined so that one atom of carbon-12 has a mass of exactly 12 amu. Since Avogadro's number was chosen so that the molar mass in grams numerically equals the atomic mass in amu, carbon-12 has a molar mass of exactly 12 g/mol by definition. Other elements have non-integer molar masses for two reasons: (1) Most elements exist as mixtures of isotopes with different masses, and the atomic mass is a weighted average, and (2) Even single isotopes have masses that include binding energy effects, making them not exactly whole numbers.
Question 3: A student says, "Since 1 mole of any gas occupies 22.4 L at STP, one mole of any gas must have the same mass." Is this correct? Explain.
Reveal Answer
The student is incorrect. While one mole of any ideal gas does occupy the same volume (22.4 L) at STP, different gases have different molar masses. For example, 1 mole of H2 (molar mass 2 g/mol) weighs only 2 grams, while 1 mole of O2 (molar mass 32 g/mol) weighs 32 grams. Both occupy 22.4 L at STP. The equal volume is due to the ideal gas law - at the same temperature and pressure, equal numbers of gas molecules occupy equal volumes, regardless of the molecule's size or mass.
Question 4: A compound's formula is C3H8O. If you have 3.01 x 10^23 molecules of this compound, how many total atoms do you have? Show your reasoning.
Reveal Answer
Step 1: Count atoms per molecule of C3H8O:
3 carbon + 8 hydrogen + 1 oxygen = 12 atoms per molecule
Step 2: Determine how many molecules we have:
3.01 x 10^23 molecules = 0.5 mol (half of Avogadro's number)
Step 3: Calculate total atoms:
3.01 x 10^23 molecules x 12 atoms/molecule = 3.61 x 10^24 atoms
Alternatively: 0.5 mol molecules x 12 atoms/molecule = 6 mol atoms = 6 x 6.022 x 10^23 = 3.61 x 10^24 atoms
🚀 Next Steps
- Review any concepts that felt challenging
- Move on to the next lesson when ready
- Return to practice problems periodically for review